 This picture assumes that Joseph threw the ball to the right so that the whiffle balls lands at 1.

A ball is dropped from a height of 36 feet. After how many seconds, does the ball hit the ground? To find the value of t at this point we must solve this quadratic equation. A ball is dropped from a height of 60 feet. Find the height of the projectile 4 seconds after it is launched. Identify all of the occurrences of 't' and substitute the input in. Free Algebra Solver Parabola in Real Life Real world applications and problems. Make a Graph Graphing Calculator. X Advertisement. Problem 1 Fly Copter. Parabola's Vertex. In other words what is the maximum value of the parabola Answer.

The helicopter must be above Problem 2 Joseph threw a whiffle ball out of a window that is four units high. Show Answer. This picture assumes that Joseph threw the ball to the right so that the whiffle balls lands at 2 You can solve this quadratic by factoring or by using the quadratic formula. Problem 3 Down in the street, Eric caught the ball and then he ran to 10 feet away from the base of the building.

## Parabola in Real Life

Problem 4 A ball is dropped from a height of 36 feet. However, only the positive solution is valid since we are measuring seconds. Problem 5 A ball is dropped from a height of 60 feet. Step 1 Identify all of the occurrences of 't' and substitute the input in. Step 2 Compute result.

## What are the Zeros of a Quadratic Function

Content on this page requires a newer version of Adobe Flash Player. At this point a quick sketch of the situation is probably in order so we can see just what is going on. In the sketch we will assume that the two cars have traveled long enough so that they are miles apart. Using the quadratic formula and simplifying that answer gives,. So, it looks like the car A traveled for Notice as well that this is NOT the second solution without the negative this time, unlike the first example.

We know the time spent working together 2 hours so we need to work rates of each machine. Here are those computations. In fact, they will need to so we can solve for it! Plugging into the word equation gives,. Machine B will need 4. Again, unlike the first example, note that the time for Machine B was NOT the second solution from the quadratic without the minus sign.

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